Question 174124This question is from textbook algebra 1
: Find 5 points that do not satisfy the equation 5y+3x=-13 This question is from textbook algebra 1
You can put this solution on YOUR website! i guess the easiest way to do this would be:
let y = 0
solve for x.
3x = -13
x = -13/3 which is roughly -4.333
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the coordinates (-13/3,0) DO satisfy this equation.
unless the line is vertical, no other y value using that x value will satisfy the equation.
we take:
(-13/3,1 or 2 or 3 or 4 or 5) and your requirements are satisfied.
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another way to do this is to graph the equation and then pick any points not on the line.
the graph of that equation would be as follows:
you start with:
5y + 3x = -13
you subtract 3x from both sides:
5y = -3x - 13
you divide both sides by 5:
y = -3/5*x - 13/5
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that's your equation in slope intercept form and also in graphable form.
the graph looks like this:
look below the graph for further comments.
you look for any point NOT on the line.
you can see that:
(-13/3,1 or 2 or 3 or 4 or 5) are NOT on the line.
you can also substitute in the equation to see that they are not on the line and do not, therefore, satisfy the equation.
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the equation:
5y + 3x = -13
take the point (-13/3,1)
your equation becomes:
5*1 + 3*(-13/3) = -13
this becomes:
5 - 13 = -13
this is clearly false.
y had to be 0 to satisfy this.
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