SOLUTION: I need your help! Problem 1. Elimination method. Type an integer or a decimal 0.05x+0.25y=66 0.15x+0.05y=72 On this problem I keep coming up with(x, y) = (3, 5,-0.5) and e

Algebra ->  Rational-functions -> SOLUTION: I need your help! Problem 1. Elimination method. Type an integer or a decimal 0.05x+0.25y=66 0.15x+0.05y=72 On this problem I keep coming up with(x, y) = (3, 5,-0.5) and e      Log On


   



Question 174118: I need your help! Problem 1. Elimination method. Type an integer or a decimal
0.05x+0.25y=66
0.15x+0.05y=72
On this problem I keep coming up with(x, y) = (3, 5,-0.5) and each time the answer is wrong. What am I doing wrong?


2. Soybean meal is 18% protein: cornmeal is 9% protein. How many pounds of each should be mixed together in order to get 360-ld mixture that is 17% protein.
Pounds of cornmeal that should be in mixture?
Pounds of soybean meal should be in mixture?

Found 2 solutions by nycsub_teacher, josmiceli:
Answer by nycsub_teacher(90) About Me  (Show Source):
You can put this solution on YOUR website!
2. Soybean meal is 18% protein: cornmeal is 9% protein. How many pounds of each should be mixed together in order to get 360-ld mixture that is 17% protein.
Pounds of cornmeal that should be in mixture?
Pounds of soybean meal should be in mixture?

first mixture + second mixture = total mixture

0.18x + 0.09x = 360(0.17)
0.18x + 0.09x(360 - x) = 0.17(360)
Can you take it from here?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
.05x+%2B+.25y+=+66
.15x+%2B+.05y+=+72
What I would do is multiply both equations by
100 to get rid of all decimals
(1) 5x+%2B+25y+=+6600
(2) 15x+%2B+5y+=+7200
Now multiply (2) by 5 and subtract (1) from it
(2) 75x+%2B+25y+=+36000
(1) 5x+%2B+25y+=+6600
(3) 70x+=+29400
x+=+420
Substitute this into ((1) or (2)
(1) 5x+%2B+25y+=+6600
5%2A420+%2B+25y+=+6600
2100+%2B+25y+=+6600
25y+=+4500
y+=+180
The answer is x+=+420 and y+=+180
check:
(2) 15x+%2B+5y+=+7200
15%2A420+%2B+5%2A180+=+7200
6300+%2B+900+=+7200
7200+=+7200
OK
---------------------------
Let c= pounds of cornmeal reeded
Let s= pounds of soybeans needed
Given is
c+%2B+s+=+360 lbs
In words:
(pounds of protein from soybeans) + (pounds of protein from cornmeal)
divided by (total pounds of mixture) = % protein in mixture
%28.18s+%2B+.09c%29+%2F+360+=+.17
multiply both sides by 360
.18s+%2B+.09c+=+61.2
Multiply both sides by 100
(1) 18s+%2B+9c+=+6120 and, given is
(2) s+%2B+c+=+360
Multiply (2) by 18 and subtract (1) from (2)
(1) 18s+%2B+9c+=+6120
(2) 18s+%2B+18c+=+6480
(3) 9c+=+360
c+=+40 and,since
s+%2B+c+=+360
s+%2B+40+=+360
s+=+320
40 pounds of cornmeal and 320 pound of soybeans are needed
check:
(1) 18s+%2B+9c+=+6120
18%2A320+%2B+9%2A40+=+6120
5760+%2B+360+=+6120
6120+=+6120
OK