Question 174044: 24x^3z^2/6y^2/8xz^4/3y^4
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 24x^3z^2/6y^2/8xz^4/3y^4
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Invert the denominator and multiply to get:
[24x^3z^2/6y^2] * [3y^4/8xz^4]
Cancel factors that are common to a numerator and a denominator,
such as 8, x, z^2,y^2, to get:
= [3x^2*y2/2z^2]
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Cheers,
Stan H.
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