SOLUTION: c^2-3c-10/c^2+5c-14 * c^2-c-2/c^2-2c-15 How do you find the illegal values in those fractions. The equation before the slash is the numerator.

Algebra ->  Equations -> SOLUTION: c^2-3c-10/c^2+5c-14 * c^2-c-2/c^2-2c-15 How do you find the illegal values in those fractions. The equation before the slash is the numerator.       Log On


   

Question 174008: c^2-3c-10/c^2+5c-14 * c^2-c-2/c^2-2c-15
How do you find the illegal values in those fractions. The equation before the slash is the numerator.
Found 2 solutions by Mathtut, solver91311:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
by setting anything in the denominators to zero....since anything divided by zero is undefined
:
so set c%5E2%2B5c-14=0 and solve and set c%5E2-2c-15=0 and solve....those
:
will be the values c cannot have.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
You mean the expression before the slash is the numerator. A thing is not an equation unless it contains an equal sign somewhere.

%28%28c%5E2-3c-10%29%2F%28c%5E2%2B5c-14%29%29%28%28c%5E2-c-2%29%2F%28c%5E2-2c-15%29%29

By 'illegal' values, I presume you mean values that make the given relation undefined. Since these are rational expressions, you need to find the values of the variable that would make the denominators be zero.

All you need to do is solve the two quadratic equations c%5E2%2B5c-14=0 and c%5E2-2c-15=0. Fortunately, both of them factor to integer roots, so this shouldn't be a particularly onerous task.