SOLUTION: Hi, I am trying to solve for "y" in this equation but I don't know where to start. {{{x = (y^3/512) + (3y^2/64) + (3y/8) + (1)

Algebra ->  Trigonometry-basics -> SOLUTION: Hi, I am trying to solve for "y" in this equation but I don't know where to start. {{{x = (y^3/512) + (3y^2/64) + (3y/8) + (1)       Log On


   

Question 173909: Hi, I am trying to solve for "y" in this equation but I don't know where to start.
x = (y^3/512) + (3y^2/64) + (3y/8) + (1)
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

x+=+%28y%5E3%2F512%29+%2B+%283y%5E2%2F64%29+%2B+%283y%2F8%29+%2B+%281%29

x+=+%28y%2F8+%2B+1%29%5E3

Take cube roots of both sides:

root%283%2Cx%29+=+root%283%2C%28y%2F8+%2B+1%29%5E3%29

root%283%2Cx%29+=+y%2F8+%2B+1

Multiply thru by 8

8root%283%2Cx%29+=+y+%2B+8

8root%283%2Cx%29+-8+=+y+

8%28root%283%2Cx%29-1%29=y

y=8%28root%283%2Cx%29-1%29

Edwin