SOLUTION: I have eight more quarters than dimes. If the coins are worth $6.20, how many dimes are there?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: I have eight more quarters than dimes. If the coins are worth $6.20, how many dimes are there?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 173872: I have eight more quarters than dimes. If the coins are worth $6.20, how many dimes are there?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
$6.20 is the same as 620 cents. If you have d dimes, then they are worth 10d cents. If you have 8 more quarters than dimes you have d + 8 quarters and the quarters are worth 25(d+8) cents
So: 10d + 25( d + 8 ) = 620 cents

Remove parentheses with the distributive property:

10d + 25d + 200 = 620

35d = 420

so d = 420/35

You can do the arithmetic.