SOLUTION: I'm having problems figuring these type for problems can you help? 6+2i/1+i

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Question 173856: I'm having problems figuring these type for problems can you help?
6+2i/1+i
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Division by complex numbers is really multiplication in disguise.
Multiply by the complex conjugate of the denominator.
%286%2B2i%29%2F%281%2Bi%29=%28%286%2B2i%29%2F%281%2Bi%29%29%2A%28%281-i%29%2F%281-i%29%29
%286%2B2i%29%2F%281%2Bi%29=%28%286%2B2i%29%2A%281-i%29%29%2F%28%281%2Bi%29%2A%281-i%29%29
Let's work out the numerator first, similar to the FOIL method,
%286%2B2i%29%2A%281-i%29=6-6i%2B2i-2i%5E2
%286%2B2i%29%2A%281-i%29=6-4i%2B2
%286%2B2i%29%2A%281-i%29=8-4i
Next the denominator,
%281%2Bi%29%2A%281-i%29=1-i%2Bi-i%5E2
%281%2Bi%29%2A%281-i%29=1-%28-1%29
%281%2Bi%29%2A%281-i%29=2
Now put it all together,
%286%2B2i%29%2F%281%2Bi%29=%28%286%2B2i%29%2A%281-i%29%29%2F%28%281%2Bi%29%2A%281-i%29%29
%286%2B2i%29%2F%281%2Bi%29=%288-4i%29%2F2
%286%2B2i%29%2F%281%2Bi%29=4-2i