SOLUTION: can you please help me with this question. Find the x and y intercepts, if they exist for the following. 3.6x^2 + 4.9y^2= 176.4

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: can you please help me with this question. Find the x and y intercepts, if they exist for the following. 3.6x^2 + 4.9y^2= 176.4       Log On


   

Question 173831: can you please help me with this question.
Find the x and y intercepts, if they exist for the following.
3.6x^2 + 4.9y^2= 176.4
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
For the x-intercepts, set y=0 and solve for x.
6x%5E2+%2B+4.9y%5E2=+176.4
6x%5E2=+176.4
x%5E2=++29.4
x=0+%2B-+5.422
(-5.422,0)
(5.422,0)
.
.
.1
For the y-intercepts, set x=0 and solve for y.
6x%5E2+%2B+4.9y%5E2=+176.4
4.9y%5E2=+176.4
y%5E2=++36
y=0+%2B-+6
(0,-6)
(0,6)
.
.
.