SOLUTION: Find the perimeter and the area of the figure L = 3/(x+4) w = 2/(x-5)

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Question 173810This question is from textbook Introductory Algebra
: Find the perimeter and the area of the figure
L = 3/(x+4)
w = 2/(x-5) This question is from textbook Introductory Algebra

Found 2 solutions by stanbon, checkley77:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Find the perimeter and the area of the figure
L = 3/(x+4)
w = 2/(x-5)
-----------------
Perimeter = 2(L+W)
= 2(3/(x+4) + 2/(x-5))
= 6/(x+4) + 4/(x-5)
= [6(x-5) + 4(x+4)]/[(x-5)(x+4)]
= [10x-14]/[x^2-x-20]
=============================
Area = LW = [3/(x+4)] = 6/[x^2-x-20]
=============================
Cheers,
Stan H.

Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website!
L = 3/(x+4)
w = 2/(x-5)
PERIMETER=2L+2W
P=2[3/(X+4)]+2[2/(X-5)
P=6/(X+4)+4/(X-5)
P=[6(X-5)+4(X+4)]/(X+4)(X-5)
P=(6X-30+4X+16]/(X+4)(X-5)
P=(10X-14)/(X+4)(X-5)
P=2(5X-7)/(X+4)(X-5) IS THE PERIMETER.
AREA=L*W
AREA=3/(X+4)*2/(X-5)
AREA=6/(X^2-X-20) IS THE AREA.