SOLUTION: Given that f(x) = x2 + 3 and D = {reals}, find f(-3). Given that g(x) = x + 4 and D = {reals}, find g(3). Given that f(x) = 3x + 1 and D = {integers}, find f(-2). Given that h(x

Algebra ->  Functions -> SOLUTION: Given that f(x) = x2 + 3 and D = {reals}, find f(-3). Given that g(x) = x + 4 and D = {reals}, find g(3). Given that f(x) = 3x + 1 and D = {integers}, find f(-2). Given that h(x      Log On


   

Question 173684: Given that f(x) = x2 + 3 and D = {reals}, find f(-3).
Given that g(x) = x + 4 and D = {reals}, find g(3).
Given that f(x) = 3x + 1 and D = {integers}, find f(-2).
Given that h(x) = x2 - 3 and D = {reals, find h(-4).
Given that g(x) = 2x - 1 and D = {integers}, find g(5).
Given that f(x) = 3x + 1 and D = {reals}, find f(-6).
Given that f(x) = x2 -2x and D = {reals}, find f(2).
Given that f(x) = x - 3 and D = {reals}, find f(-2).
Given that f(x) = 2x2 and D = {reals}, find f(4).
Given that f(x) = 2x3 and D = (reals}, find f(2).
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Given f(x) = some function of x, to evaluate f(a), just substitute a for x whereever it occurs in the function and do the arithmetic. I presume D stands for domain, so since all of your values are integers, you don't have any excluded values in any of the stated domains.

Here's how to do the first one:
Given that f%28x%29+=+x%5E2+%2B+3 and D = {reals}, find f%28-3%29.

f%28-3%29=%28-3%29%5E2%2B3=9%2B3=12

Do the rest of them the same way.