|
Question 173682: 1. what is the equation of the line containing the given pair of points of (4,6) and (-10 , 15)
2. solve -3x - 4y+2z = -6
3. solve 4x - 6y + 3z = 8
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! 1. what is the equation of the line containing the given pair of points of (4,6) and (-10 , 15)
You can do this the hard way:
Find the slope, m, = (diff in y)/diff in x)
m = (6-15)/(4+10)
m = -9/14
then y-y1 = m*(x-x1) (x1,y1) is either point
y - 6 = (-9/14)*(x - 4)
y-6 = -9x/14 + 18/7
y = -(9/14)x + 60/7 slope-intercept form
9x + 14y = 120 standard form
---------------
The easy way:
|+x +y +1|
|+4 +6 +1| = 0
|-10 15 1|
x*(6-15) -y*(4+10) + (60 +60) = 0
-9x - 14y + 120 = 0
9x + 14y = 120
---------------
2. solve -3x - 4y+2z = -6
That's 1 equation in 3 unknowns. It's a plane in 3-space. It can't be "solved"
3. solve 4x - 6y + 3z = 8
Same as #2
|
|
|
| |
