SOLUTION: gragh that passes through (-1,5)parallel to a line whose slope is -0.3

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Question 173674: gragh that passes through (-1,5)parallel to a line whose slope is -0.3
Found 2 solutions by Mathtut, jojo14344:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
use point slope formula which states that y-k=m(x-h) where m is the slope and (h,k) is any point on the line
:
y-5=-.3(x-(-1))
:
y-5=-.3x-.3
:
highlight%28y=-.3x%2B4.7%29
:
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C-.3x%2B4.7%29

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

Remember, Parallel Lines have the same SLOPE: m%5B1%5D=m%5B2%5D=-0.30
Thru points (-1,5):y=mx%2Bb
5=-1%28-0.30%29%2Bb
5=0.30%2Bb
b=5%2B%28-0.30%29=4.70, y-intercept
It follows eqn: ------>y=-0.30x%2B4.70
See the graph:

thank you,
Jojo