SOLUTION: Log(x+99)-Logx=2

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Question 173669: Log(x+99)-Logx=2
Answer by Alan3354(69443) About Me  (Show Source):
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Log(x+99)-Logx=2
log((x+99)/x) = 2 Subtraction of logs --> division
raise 10 to the power of both sides
(x+99)/x = 100
x+99 = 100x
99 = 99x
x = 1