SOLUTION: use synthetic division to find the height of an object, 3.5 seconds after launch, where the height, in feet, above the ground is given by: h(t)=-16t^2 + 112t + 128
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Question 173600: use synthetic division to find the height of an object, 3.5 seconds after launch, where the height, in feet, above the ground is given by: h(t)=-16t^2 + 112t + 128 Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! h(t)=-16t^2+112t+128
H(3.5)=16*3.5^2+112*3.5+128
H(3.5)=16*12.25+392+128
H(3.5)=196+392+128
H(3.5)=716 FT.
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