Question 173579: Log6-log6(x-1)=1
Answer by nycsub_teacher(90)   (Show Source):
You can put this solution on YOUR website! Log_6 - log_6(x-1)= 1
Use the property of subtraction for logs.
I will use log_6 to mean "log base 6."
log_6(1/(x - 1) = 1
Remove the word log and raise 6 to the value as given on the other side of the equation.
6^1 = 1/(x - 1)
6 = 1(x - 1)
Solve for x.
6(x - 1) = 1
6x - 6 = 1
6x = 6 + 1
6x = 7
x = 7/6
x = 1.2
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