Question 173572: Solve y=log2(5x-4)
y=3+log2(x-1)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Solve
y= log2(5x-4)
y= 3+log2(x-1)
-------------
Substitute to get:
log2 (5x-4) = 3 + log2 (x-1)
log2 (5x-4) - log2 (x-1) = 3
log2 [(5x-4)/(x-1)] = 3
[(5x-4)/(x-1)] = 2^3
5x-4 = 8(x-1)
5x-4 = 8x - 8
3x = 4
x = 4/3
================================
Cheers,
Stan H.
|
|
|
