SOLUTION: How can I solve these Equations? ( solving fractional equations) 1. 4/3x+1/3=1 2. y+3/2y=2\3 3. 3/2z+1/z=1/2 5. 9/2b+7=3/b

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: How can I solve these Equations? ( solving fractional equations) 1. 4/3x+1/3=1 2. y+3/2y=2\3 3. 3/2z+1/z=1/2 5. 9/2b+7=3/b      Log On


   

Question 173530This question is from textbook Amsco's Mathematics B
: How can I solve these Equations? ( solving fractional equations)

1. 4/3x+1/3=1
2. y+3/2y=2\3
3. 3/2z+1/z=1/2
5. 9/2b+7=3/b This question is from textbook Amsco's Mathematics B

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How can I solve these Equations? ( solving fractional equations)
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Multiply thru by whatever eliminates the fractions.
In #1, multiply by 3.
1. 4/3x+1/3=1 (I'll assume that's (4/3)x, and not 4/(3x).
4x + 1 = 3
4x = 2
x = 1/2
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2. y+3/2y=2\3
I don't know what to do with \
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3. 3/2z+1/z=1/2
Multiply by 2z
3+2 = z
z = 5
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5. 9/2b+7=3/b
You do this one.