SOLUTION: Solve for x 2^(x^2)=32(2^(4x))

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve for x 2^(x^2)=32(2^(4x))       Log On


   

Question 173507: Solve for x
2^(x^2)=32(2^(4x))
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
2%5E%28x%5E2%29=32%282%5E%284x%29%29
2%5E%28x%5E2%29=2%5E5+%2A+%282%5E%284x%29%29
2%5E%28x%5E2%29=2%5E%28%284x+%2B+5%29%29
x%5E2+=+4x+%2B+5
x%5E2+-+4x+-+5+=+0
x-5%29%28x%2B1%29=+0
x = 5 or x = -1
check your answers by plugging these two values into the original equation. See if none, one or both work. let me know if you can't take it in from here