SOLUTION: 1/(2X-4)- 2/(y+1)=0 and 1/(x-3)- 1/(y+4)=0 Solve using elimination:

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Question 173478: 1/(2X-4)- 2/(y+1)=0 and 1/(x-3)- 1/(y+4)=0
Solve using elimination:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
1/(2X-4)- 2/(y+1)=0 and 1/(x-3)- 1/(y+4)=0
Solve using elimination:
:
1%2F%28%282X-4%29%29- 2%2F%28%28y%2B1%29%29 = 0
Multiply equation by (2x-4)(y+1) to get rid of the denominators, results
(y+1) - 2(2x-4) = 0
y + 1 - 4x + 8 = 0
-4x + y + 9 = 0
-4x + y = -9
4x - y = 9; multiplied by -1
and
1%2F%28%28x-3%29%29 - 1%2F%28%28y%2B4%29%29 = 0
Multiply by (x-3)(y+4), results:
(y + 4) - (x - 3) = 0
y + 4 - x + 3 = 0
-x + y + 7 = 0
-x + y = -7
:
Add the two equations
4x - y = 9
-x + y = -7;
---------------adding eliminates y, find x
3x = 2
x = 2%2F3
:
Use the last equation to find y:
-2%2F3 + y = -7
y = -7 + 2%2F3
y = -61%2F3 or -19%2F3
:
:
Check solutions in the 2nd original equation:
1%2F%28%28%282%2F3%29-3%29%29 - 1%2F%28%28%28-19%2F3%29%2B4%29%29 = 0
1%2F%28%28%282%2F3%29-%289%2F3%29%29%29 - 1%2F%28%28%28-19%2F3%29%2B%2812%2F3%29%29%29 = 0
1%2F%28%28-7%2F3%29%29 - 1%2F%28%28-7%2F3%29%29 = 0
-3%2F7 + 3%2F7 = 0
:
I'll let you check it in the 1st original equation