SOLUTION: A food store makes a 9-lb mixture of peanuts. cashews, and raisens. Peanuts cost $1.50 per pound, cashews cost $2.00 per pound, and raisens cost $1.00 per pound. The mixture calls

Algebra ->  College  -> Linear Algebra -> SOLUTION: A food store makes a 9-lb mixture of peanuts. cashews, and raisens. Peanuts cost $1.50 per pound, cashews cost $2.00 per pound, and raisens cost $1.00 per pound. The mixture calls       Log On


   



Question 173475: A food store makes a 9-lb mixture of peanuts. cashews, and raisens. Peanuts cost $1.50 per pound, cashews cost $2.00 per pound, and raisens cost $1.00 per pound. The mixture calls for twice as much peanuts than cashews. The total cost of the mixture is $13.00. How much of each ingredient did the store use?
How do you det this up into equations?

Found 2 solutions by Mathtut, josmiceli:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
let the number of peanuts, cashews, and raisens be p,c,and r respectively
:
p+c+r=9........eq 1----->r=9-p-c
1.5p+2c+1r=13..eq 2
p=2c...........eq 3
:
lets plug p's value in eq 3 into eq 1 and 2 and re write them
:
2c+c+r=9.........eq (4)
1.5(2c)+2c+r=13..eq (5)
:
3c+r=9.... eq (4)
5c+r=13... eq (5)
:
now lets subtract eq 5 from eq 4
:
-2c=-4
:
highlight%28c=2%29pounds of cashews
:
highlight%28p=2c=2%282%29=4%29pounds of peanuts
:
highlight%28r=9-p-c=9-2-4=3%29pounds of raisens

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
These problems are always easier if you put letters in place
of the things you're looking for:
Let p= the pounds of peanuts needed
Let c= the pounds of cashews needed
Let r= the pounds of raisins needed
The 1st sentence says it's a 9-pound mixture, so
(1) p+%2B+c+%2B+r+=+9
Peanuts cost $1.50 per pound, so the cost of the peanuts will be
1.5p
Cashews cost $2.00 per pound, so the cost of the cashews will be
2c
Raisins cost $1.00 per pound, so the cost of the raisins will be
1%2Ar
The total cost of the mixture is $13.00, so
(2) 1.5p+%2B+2c+%2B+r+=+13
The mixture calls for twice as much peanuts than cashews, so
(3) p+=+2c
Now I have 3 equations and 3 unknowns, so it should be solvable
Subtract (1) from (2)
.5p+%2B+c+=+4
Substitute (3) for p
.5%2A%282c%29+%2B+c+=+4
2c+=+4
c+=+2
And, going back to (3),
p+=+2c
p+=+2%2A2
p+=+4
Use (1) to find r
p+%2B+c+%2B+r+=+9
4+%2B+2+%2B+r+=+9
6+%2B+r+=+9
r+=+3
The amounts of the ingredients are 2 pounds of cashews,
4 pounds of peanuts, and 3 pounds of raisins
Check answer:
(2) 1.5p+%2B+2c+%2B+r+=+13
1.5%2A4+%2B+2%2A2+%2B+3+=+13
6+%2B+4+%2B+3+=+13
13+=+13
OK