SOLUTION: The Great Pyramid of Cheops has a square base of 771ft. on a side and a height of 486ft. How many apartments 35ft x 20ft. x 8ft. would be needed to have a volume equivalent to that

Algebra ->  Volume -> SOLUTION: The Great Pyramid of Cheops has a square base of 771ft. on a side and a height of 486ft. How many apartments 35ft x 20ft. x 8ft. would be needed to have a volume equivalent to that      Log On


   

Question 173462: The Great Pyramid of Cheops has a square base of 771ft. on a side and a height of 486ft. How many apartments 35ft x 20ft. x 8ft. would be needed to have a volume equivalent to that of the Great Pyramids?
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
V of a pyramid is L*W of the base times the 1/3 height
:
771(771)(486)/3=96299442 cu ft in the pyramid
:
cubic feet of 1 apt is 35(20)(8)=5600
:
so we need to divide the Volume of the pyramid by the volume of the apt to get the number of apartment units that would fit in this pyramid
:
96233442/5600= appx. 17196 units is what it would have taken to fill this pyramid.