SOLUTION: a+2c+3E+2F=270 2a+b+2d+2f=240 3a+4b+c+f=360 a+5c+2e=440

Algebra ->  Matrices-and-determiminant -> SOLUTION: a+2c+3E+2F=270 2a+b+2d+2f=240 3a+4b+c+f=360 a+5c+2e=440      Log On


   

Question 173447: a+2c+3E+2F=270
2a+b+2d+2f=240
3a+4b+c+f=360
a+5c+2e=440
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
a+2c+3E+2F=270
2a+b+2d+2f=240
3a+4b+c+f=360
a+5c+2e=440
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Even assuming the E is the same as e, and F is f, you have 4 equations in 6 unknowns. That is not sufficient. You have to have 6 eqns if there are 6 unknowns.