SOLUTION: I just want to make sure I 'm on the right track.Factoring x^2-5x+24 x^2+3x-40 x^2-9/16

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Question 173380: I just want to make sure I
'm on the right track.Factoring
x^2-5x+24
x^2+3x-40
x^2-9/16

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
# 1




Looking at the expression x%5E2-5x%2B24, we can see that the first coefficient is 1, the second coefficient is -5, and the last term is 24.


Now multiply the first coefficient 1 by the last term 24 to get %281%29%2824%29=24.


Now the question is: what two whole numbers multiply to 24 (the previous product) and add to the second coefficient -5?


To find these two numbers, we need to list all of the factors of 24 (the previous product).


Factors of 24:
1,2,3,4,6,8,12,24
-1,-2,-3,-4,-6,-8,-12,-24


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 24.
1*24
2*12
3*8
4*6
(-1)*(-24)
(-2)*(-12)
(-3)*(-8)
(-4)*(-6)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -5:


First NumberSecond NumberSum
1241+24=25
2122+12=14
383+8=11
464+6=10
-1-24-1+(-24)=-25
-2-12-2+(-12)=-14
-3-8-3+(-8)=-11
-4-6-4+(-6)=-10



From the table, we can see that there are no pairs of numbers which add to -5. So x%5E2-5x%2B24 cannot be factored.







# 2




Looking at the expression x%5E2%2B3x-40, we can see that the first coefficient is 1, the second coefficient is 3, and the last term is -40.


Now multiply the first coefficient 1 by the last term -40 to get %281%29%28-40%29=-40.


Now the question is: what two whole numbers multiply to -40 (the previous product) and add to the second coefficient 3?


To find these two numbers, we need to list all of the factors of -40 (the previous product).


Factors of -40:
1,2,4,5,8,10,20,40
-1,-2,-4,-5,-8,-10,-20,-40


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -40.
1*(-40)
2*(-20)
4*(-10)
5*(-8)
(-1)*(40)
(-2)*(20)
(-4)*(10)
(-5)*(8)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 3:


First NumberSecond NumberSum
1-401+(-40)=-39
2-202+(-20)=-18
4-104+(-10)=-6
5-85+(-8)=-3
-140-1+40=39
-220-2+20=18
-410-4+10=6
-58-5+8=3



From the table, we can see that the two numbers -5 and 8 add to 3 (the middle coefficient).


So the two numbers -5 and 8 both multiply to -40 and add to 3


Now replace the middle term 3x with -5x%2B8x. Remember, -5 and 8 add to 3. So this shows us that -5x%2B8x=3x.


x%5E2%2Bhighlight%28-5x%2B8x%29-40 Replace the second term 3x with -5x%2B8x.


%28x%5E2-5x%29%2B%288x-40%29 Group the terms into two pairs.


x%28x-5%29%2B%288x-40%29 Factor out the GCF x from the first group.


x%28x-5%29%2B8%28x-5%29 Factor out 8 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x%2B8%29%28x-5%29 Combine like terms. Or factor out the common term x-5

---------------------------------------------


Answer:


So x%5E2%2B3x-40 factors to %28x%2B8%29%28x-5%29.


Note: you can check the answer by FOILing %28x%2B8%29%28x-5%29 to get x%5E2%2B3x-40 or by graphing the original expression and the answer (the two graphs should be identical).







# 3




x%5E2-9%2F16 Start with the given expression.


%28x%29%5E2-9%2F16 Rewrite x%5E2 as %28x%29%5E2.


%28x%29%5E2-%283%2F4%29%5E2 Rewrite 9%2F16 as %283%2F4%29%5E2.


Notice how we have a difference of squares A%5E2-B%5E2 where in this case A=x and B=3%2F4.


So let's use the difference of squares formula A%5E2-B%5E2=%28A%2BB%29%28A-B%29 to factor the expression:


A%5E2-B%5E2=%28A%2BB%29%28A-B%29 Start with the difference of squares formula.


%28x%29%5E2-%283%2F4%29%5E2=%28x%2B3%2F4%29%28x-3%2F4%29 Plug in A=x and B=3%2F4.


So this shows us that x%5E2-9%2F16 factors to %28x%2B3%2F4%29%28x-3%2F4%29.


In other words x%5E2-9%2F16=%28x%2B3%2F4%29%28x-3%2F4%29.