Question 173159: please help me solve for Q
5+Q/40=845/Q+5+Q/80
Answer by nycsub_teacher(90)   (Show Source):
You can put this solution on YOUR website! It is very important to put parentheses and brackets around quantities because otherwise the questions have no meaning.
I understood your set up this way:
(5 + Q)/40 = 845/(Q + 5) + (Q/80)
Is this the fractional equation that you are trying to solve for Q?
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I received your e-mail. I will set it up and let you finish the problem.
We want to remove the fraction from both sides of the equation.
To do this, multiply both sides by the LCD.
After multiplication, this is what we have:
2(Q + 5)(Q + 5) = 67600 + Q(Q + 5)
We continue to break it down like this:
2(Q^2 + 10Q + 25) = 67600 + Q^2 + 5Q
2Q^2 + 20Q + 50 = 67600 + Q^2 + 5Q
Bring everything on the right side to the left but do not forget to change the sign of the terms you are moving to the left side.
2Q^2 + 20Q + 50 - Q^2 - 5Q - 67600 = 0
Q^2 + 15Q - 67550 = 0...This is a quadratic equation.
I'll let you take over from here on. To solve for Q, it is best to use the quadratic formula.
Understood?
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