SOLUTION: A painter can paint a room three hours less than an apprentice. Together they can pain the room in two hours. How long will it take the apprentice working alone to paint the room?

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Question 172994: A painter can paint a room three hours less than an apprentice. Together they can pain the room in two hours. How long will it take the apprentice working alone to paint the room?
Found 2 solutions by Mathtut, gonzo:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
lets call the appretices time per hour 1/a and painter 1/a-3
:
1%2F%28a%2B1%29%2B1%2F%28a-3%29 is what they can do together per hour.
:
if it takes 2 hours together we have
:
2%281%2F%28a%2B1%29%2B1%2F%28a-3%29%29=2
:
2%28%28a-3%29%2Ba%29=a%28a-3%29multiplying each term by a(a-3)
:
2a-6%2B2a=a%5E2-3adistributing
:
a%5E2-7a%2B6=0combining like terms
a=1 and 6
:
throw out 1 because that would make the painters time negative so
:
highlight%28a=6%29hours alone for the apprentice to paint the room
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-7x%2B6+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-7%29%5E2-4%2A1%2A6=25.

Discriminant d=25 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--7%2B-sqrt%28+25+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-7%29%2Bsqrt%28+25+%29%29%2F2%5C1+=+6
x%5B2%5D+=+%28-%28-7%29-sqrt%28+25+%29%29%2F2%5C1+=+1

Quadratic expression 1x%5E2%2B-7x%2B6 can be factored:
1x%5E2%2B-7x%2B6+=+%28x-6%29%2A%28x-1%29
Again, the answer is: 6, 1. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-7%2Ax%2B6+%29


Answer by gonzo(654) About Me  (Show Source):
You can put this solution on YOUR website!
formula to work with is:
rate * time = number of units
the number of units is 1 room.
it takes the painter x - 3 hours to paint a room.
it take the apprentice x hours to paint the same room.
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let Rp = rate of the painter.
let Ra = rate of the apprentice.
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since rate * time = number of units,
for the painter:
Rp * (x-3) = 1
for the apprentice:
Ra * (x) = 1
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if they are both working together, it takes 2 hours to paint the room.
working together their rates are additive.
since rate * time = number of units,
for both:
2 * (Ra + Rp) = 1
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for the apprentice:
Ra * x = 1
which means:
Ra = 1/x
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for the painter:
Rp * (x-3) = 1
which means:
Rp = 1/(x-3)
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substituting for Ra and Rp, the formula:
2 * (Ra + Rp) = 1
becomes:
2+%2A+%281%2Fx+%2B+1%2F%28x-3%29%29+=+1
which becomes:
2%2Fx+%2B+2%2F%28x-3%29+=+1
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if we multiply both sides of the equation by x*(x-3), we get:
2%2A%28x-3%29+%2B+2%2Ax+=+x%2A%28x-3%29
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this becomes:
2%2Ax+-+6+%2B+2%2Ax+=+x%2A%28x-3%29
which becomes:
4%2Ax+-+6+=+x%5E2+-+3%2Ax
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if we subtract 4*x from both sides of the equation, and if we add 6 to both sides of the equation, we get:
0+=+x%5E2+-+7%2Ax+%2B+6
which is the same as:
x%5E2+-+7%2Ax+%2B+6+=+0
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this factors out to be:
%28x-1%29%2A%28x-6%29+=+0
which give us:
x = 1
or:
x = 6
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x cannot be 1, since x-3 would be negative which is not possible.
x must be 6.
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if x is 6, then
x-3 is 3.
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since x * Ra = 1
then Ra must be 1/6
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since (x-3)*Rp = 1
then Rp must be 1/3
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to prove this is true, we substitute in the original equations to see if they are true.
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first equation:
x * Ra = 1
6 * 1/6 = 1 is true.
second equation:
(x-3)*Rp = 1
(6-3)*1/3 = 1
3*1/3 = 1 is true.
third equation:
2 * (Ra + Rp) = 1
2 * (1/6 + 1/3) = 1
2 * (1/6 + 2/6) = 1
2 * (3/6) = 1
6/6 = 1 which is true.
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answer of x = 6 looks good.
apprentice takes 6 hours to paint a room.
painter takes 6-2 = 3 hours to paint the same room.
together they can paint the room in 2 hours.
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