SOLUTION: This one is kind of difficult for me. Can you help with this? For a certain angle and a certain water pressure, the path of the water from a hose a fire scene can be modeled by

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Question 172985: This one is kind of difficult for me. Can you help with this?
For a certain angle and a certain water pressure, the path of the water from a hose a fire scene can be modeled by the quadratic equation h=16^2+80t+4, where "h" is the high of the water above ground in feet and "t" is the time in seconds after the water has left the hose.
Find the value of h in the equation for t=0, 1, 2, 3, 4, 5 seconds.
t 0 1 2 3 4 5
h

Found 2 solutions by jim_thompson5910, Mathtut:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the first few to get you started


Let's find the value of "h" when t=0


h=16t%5E2%2B80t%2B4 Start with the given equation.


h=16%280%29%5E2%2B80%280%29%2B4 Plug in t=0.


h=16%280%29%2B80%280%29%2B4 Square 0 to get 0.


h=0%2B80%280%29%2B4 Multiply 16 and 0 to get 0.


h=0%2B0%2B4 Multiply 80 and 0 to get 0.


h=4 Combine like terms.


So when t=0, then h=4


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Let's find the value of "h" when t=1


h=16t%5E2%2B80t%2B4 Start with the given equation.


h=16%281%29%5E2%2B80%281%29%2B4 Plug in t=1.


h=16%281%29%2B80%281%29%2B4 Square 1 to get 1.


h=16%2B80%281%29%2B4 Multiply 16 and 1 to get 16.


h=16%2B80%2B4 Multiply 80 and 1 to get 80.


h=100 Combine like terms.


So when t=1, then h=100

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Let's find the value of "h" when t=2


h=16t%5E2%2B80t%2B4 Start with the given equation.


h=16%282%29%5E2%2B80%282%29%2B4 Plug in t=2.


h=16%284%29%2B80%282%29%2B4 Square 2 to get 4.


h=64%2B80%282%29%2B4 Multiply 16 and 4 to get 64.


h=64%2B160%2B4 Multiply 80 and 2 to get 160.


h=228 Combine like terms.


So when t=2, then h=228

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So we have the following so far: 


t   0    1    2    3    4    5
h   4   100  228


I'll let you do the rest.

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
h for t(0)=16%280%29%5E2%2B80%280%29%2B4=4
:
for...t(1)=16%281%29%5E2%2B80%281%29%2B4=100
:
......t(2)=16%282%29%5E2%2B80%282%29%2B4=228
:
......t(3)=16%283%29%5E2%2B80%283%29%2B4=388
:
......t(4)=16%284%29%5E2%2B80%284%29%2B4=580
:
......t(5)=16%285%29%5E2%2B80%285%29%2B4=804