Question 172720: I believe I have the answer to this one, but I need confirmation, not really sure if my steps are right:
Simplify:
(3x^2 - 9x - 3)/(3x -3)
3.x^2 - 3.3x - 3.1/3.x - 3.1=
x^2 +x-2, remainder 3?
Is this correct?
Answer by w1ldc4t(2)  (Show Source):
You can put this solution on YOUR website! (3x^2 - 9x - 3)/(3x -3)
= all can be divided by 3, so
= (x^2-3x-1)/(x-1)
USING REMAINDER THEOREM
x^2-3x-1= (Ax+B)(x-1)+ R
apply x=1
then -3 =0 + R
******************R=-3*****************
We can also find A and B,
when x=0
-1 = -B -3
B = -2
x=2
4-6-1 = (2A-2)(1) -3
0 = 2A-2
A = 1
So,
(3x^2-9x-3)= (3x-3)(x-2)+ (-3)
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