SOLUTION: 1/3logbX + 3logbY - 4logbX =

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Question 172588: 1/3logbX + 3logbY - 4logbX =
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
1/3logbX + 3logbY - 4logbX =
= log(x^(1/3)) + log(y^3) - log(x^4) (all the same base)
= log(y^3*x^(1/3)/x^4)
= log%28b%2C%28y%5E3%2Fx%5E%2811%2F3%29%29%29