SOLUTION: solve the following for x 2^x=32 3^x-2=81 4^x=1/64

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Question 172572: solve the following for x
2^x=32
3^x-2=81
4^x=1/64
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2^x=32
2^x = 2^5
x = 5
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3^x-2=81
3^(x-2)=3^4
x-2 = 4
x = 6
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4^x=1/64
4^x = 4^-3
x = -3
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Cheers,
Stan H.