Question 172517: Question provided by co-worker I'm trying to help...
Given the equation
x^2 + 6sqrt2x + y^2 - 4sqrt5y = 3
complete the square for both x and y and find the equation of the circle.
A. (x + 3sqrt2)^2 + (y - 2sqrt5)^2 = 13
B. (x + 3sqrt2)^2 + (y - 2sqrt5)^2 = 35
C. (x + 3sqrt2)^2 + (y - 2sqrt5)^2 = 38
D. (x + 3sqrt2)^2 + (y - 2sqrt5)^2 = 10
I can usually help her figure things out, or we at least muddle through them together. It's been so long, though, that I'm lost on this on.
I thank you, and she thanks you.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! x^2 + 6sqrt2x + y^2 - 4sqrt5y = 3
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[x^2 + 6sqrt(2)x + ?] + [y^2 -4sqrt(5)y + ?] = 3
x^2 + 6sqrt(2)x + (3sqrt(2))^2 + y^2 -4sqrt(5)y + (2sqrt(5))^2 = 3 +
(3sqrt(2))^2 + (2sqrt(5))^2
x^2 + 6sqrt(2)x + 18 + y^2 -4sqrt(5)y + 20 = 3 + 18 + 20
(x+3sqrt(2))^2 + (y-2sqrt(5))^2 = 41
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complete the square for both x and y and find the equation of the circle.
A. (x + 3sqrt2)^2 + (y - 2sqrt5)^2 = 13
B. (x + 3sqrt2)^2 + (y - 2sqrt5)^2 = 35
C. (x + 3sqrt2)^2 + (y - 2sqrt5)^2 = 38
D. (x + 3sqrt2)^2 + (y - 2sqrt5)^2 = 10
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Comment: The difference between the answer to your posted problem
and the answer "c" (above) is the 3 in the posted problem.
Are you sure that number is not -3 ?
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Cheers,
Stan H.
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