SOLUTION: i need to convert this rectangular equation into a polar equation: the circle centered at (0,-4), with a radius of 4. thanks!

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Question 172172: i need to convert this rectangular equation into a polar equation: the circle centered at (0,-4), with a radius of 4.
thanks!

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
i need to convert this rectangular equation into a polar equation: the circle centered at (0,-4), with a radius of 4.

The standard equation for a circle in
rectangular coordinates with center (h,k)
and radius r is:

%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2

Substitute h=0, k=-4, and r=4

%28x-0%29%5E2%2B%28y-%28-4%29%29%5E2=%284%29%5E2

x%5E2%2B%28y%2B4%29%5E2=16

x%5E2%2By%5E2%2B8y%2B16=16

x%5E2%2By%5E2%2B8y=0

Now we draw a typical angle phi in standard 
position. Unfortunately the software here can't
get the Greek letter theta, so I'll use "phi" instead. 



Write down the trig equation for the sine,
cosine, and and the Pythagorean theorem:



Solve the first two equations for 
y and x:



Now go back to this equation:

x%5E2%2By%5E2%2B8y=0

Notice we can replace the first two
terms x%5E2%2By%5E2 by r%5E2
and we get:

r%5E2%2B8y=0

Now we can replace y by
r%2Asin%28phi%29

r%5E2%2B8y=0

r%5E2%2B8r%2Asin%28phi%29=0

Factor out r:

r%28r%2B8sin%28phi%29%29=0

r=0, r%2B8sin%28phi%29=0

The first equation can be ignored. It is
just the equation of the origin (pole).
But the circle contains the origin (pole).
So we end up with:

r%2B8sin%28phi%29=0

Edwin