You can put this solution on YOUR website! simplify
(3+3i)/(5+2i)
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These are always done by multiplying the NUM and DEN by the conjugate of the DEN. The DEN here is 5+2i, so the conjugate is 5-2i.
(3+3i)/(5+2i)
=[(3+3i)*(5-2i)]/[(5+2i)*(5-2i)]
= (15-6i+15i+6)/(25+4)
= (21 + 9i)/29
You can put this solution on YOUR website! simplify
(3+3i)/(5+2i)
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Use FOIL:
F: 3*5 = 15
O: 3*2i = 6i
I: 5*3i = 15i
L: 3i*2i = -6
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Combine these to get: 9 + 21i
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Cheers,
Stan H.