SOLUTION: Find three consecutive odd integers such that three times the second minus the third is 11 more than the first.

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Question 172055: Find three consecutive odd integers such that three times the second minus the third is 11 more than the first.
Answer by Alan3354(69443) About Me  (Show Source):
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Find three consecutive odd integers such that three times the second minus the third is 11 more than the first.
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They're x, x+2 and x+4
Three times the 2nd is 3x+6
3x+6 - (x+4) = x + 11
3x #2...3rd....1st+11
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3x+6 - (x+4) = x + 11
2x + 2 = x + 11
x = 9
So they're 9, 11 and 13