SOLUTION: solve: log5(3x+1)=log5(2x+7) the 5's are bases

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Question 172041: solve: log5(3x+1)=log5(2x+7) the 5's are bases
Answer by Alan3354(69443) About Me  (Show Source):
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log5(3x+1)=log5(2x+7) the 5's are bases
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If the logs (to the same base) are equal, the binomials are equal.
3x+1 = 2x+7
x = 6
Check:
log(19) = log(19) (to any base)