SOLUTION: divide 184 into two parts such that one third of one part may exceed one seventh of the other part by 8
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-> SOLUTION: divide 184 into two parts such that one third of one part may exceed one seventh of the other part by 8
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You can put this solution on YOUR website! divide 184 into two parts such that one third of one part may exceed one seventh of the other part by 8
:
Let one part = x
and
the other part = (184-x)
:
"one third of one part may exceed one seventh of the other part by 8" x = (184-x) + 8
:
Multiply equation by 21 to get rid of the denominators; results:
7x = 3(184-x) + 21(8)
:
7x = 552 - 3x + 168
:
7x + 3x = 552 + 168
:
10x = 720
x =
x = 72 is one part
and
184 - 72 = 112 is the other part
;
:
Check these values in the statement
"one third of one part may exceed one seventh of the other part by 8" (72) = (112) + 8
24 = 16 + 8
