SOLUTION: how do you solve: log3(4x+1)=log3(5x-2), the 3's are the base numbers

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Question 171943: how do you solve: log3(4x+1)=log3(5x-2), the 3's are the base numbers
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve: log3(4x+1)=log3(5x-2)
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log3(4x+1)-log3(5x-2) = 0
log3[(4x+1)/(5x-2)] = 0
[(4x+1)/(5x-2)] = 3^0
Cross-multiply to get:
4x+1 = 5x-2
x = 3
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Cheers,
stan H.