Question 171885: The lager of two integers is 8 less than twice the smaller. When the smaller number is subtracted from the larger, the difference is 17. Find the two numbers.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Two numbers x = the larger, y = the smaller
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Write an equation for each statement:
:
"The larger of two integers is 8 less than twice the smaller."
x = 2y - 8
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"When the smaller number is subtracted from the larger, the difference is 17."
x - y = 17
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Find the two numbers.
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Using the 1st statement equation, substitute (2y-8) for x in 2nd equation
(2y-8) - y = 17
2y - y = 17 + 8
y = 25
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Then find x:
x = 2(25) - 8
x = 50 - 8
x = 42
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Check solution in the statement:
" When the smaller number is subtracted from the larger, the difference is 17."
42 - 25 = 17
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