SOLUTION: Pam jogged up a hill at 6 km/h and then jogged back down at 10 km/h. If her total jogging time was 1 h 20 min, how many km did she travel?

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Question 171795This question is from textbook Algebra and Trigonometry: Structure and Method-Book 2
: Pam jogged up a hill at 6 km/h and then jogged back down at 10 km/h. If her total jogging time was 1 h 20 min, how many km did she travel? This question is from textbook Algebra and Trigonometry: Structure and Method-Book 2

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=R*T
6*X=10(4/3-X) [4/3=1H. 20M.]
6X=40/3-10X
6X+10X=40/3
16X=40/3
X=40/3*1/16
X=40/48
X=5/6 HOURS FOR THE UP HILL RUN.
10(4/3-5/6)
10(4*4-5*2)/12
10(16-10)/12
10*6/12
60/12=5 M. IS THE RUN DOWN THE HILL.
6*5/6=30/6=5 M. UP THE HILL
tOTAL RUN=2*5=10 M. IS THE TOTAL RUN DISTANCE.