SOLUTION: what would log3 28 be and use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.

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Question 171594: what would log3 28 be and use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.
Found 2 solutions by Alan3354, nerdybill:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
what would log3 28 be
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log%283%2C28%29+=+ln%2828%29%2Fln%283%29 (or log base 10, just so they match)
log%283%2C28%29 =~ 3.0331
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and use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.
45 = 3*3*5
log%286%2C45%29+=+2%2Alog%286%2C3%29%2Blog%286%2C5%29
log%286%2C45%29+=+2%2A0.1613147+%2B+0.898244
log%286%2C45%29+=+1.2208734 or it would if log%286%2C3%29+=+0.1613147
It doesn't.
log%286%2C3%29+=+0.613147
That makes the log%286%2C45%29+=+2.1245388


Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
what would log3 28 be
log3 28 = log(28)/log(3) = 1.4472/0.4771 = 0.6905
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use log6 3= 0.1613147 and log6 5=0.898244 to find log6 45.
since we can rewrite
log6 45 = log6(5*3*3)
log6 45 = log6(5) + log6(3) + log6(3)
log6 45 = 0.898244 + 0.1613147 + 0.1613147 = 1.2208734