Question 171574: I NEED URGENT HELP WITH THESE TWO QUESTIONS. MY STEPS WERE CORRECT BUT CALCULATIONS ARE WRONG. I WANT TO REVIEW FOR MY FINALS. ALL TUTOR YOU ARE WELCOME TO ANSWER. PAID OR NOT. THANKS A BUNCH! I NEED EXPLAINED SOLUTIONS.
SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.
Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim.
6) The health of employees is monitored by periodically weighing them in. A sample of 54 employees has a mean weight of 183.9 lb. Assuming that ! is known to be 121.2 lb, use a 0.10 significance level to test the claim that the population mean of all such employees
weights is less than 200 lb.
Test the given claim using the traditional method of hypothesis testing. Assume that the sample has been randomly selected from a population with a normal distribution.
7) A large software company gives job applicants a test of programming ability and the mean for that test has been 160 in the past. Twenty-five job applicants are randomly selected from one large university and they produce a mean score and standard deviation of 183 and 12, respectively. Use a 0.05 level of significance to test the claim that this sample comes from a population with a mean score greater than 160.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 6) The health of employees is monitored by periodically weighing them in. A sample of 54 employees has a mean weight of 183.9 lb. Assuming that ! is known to be 121.2 lb, use a 0.10 significance level to test the claim that the population mean of all such employees
weights is less than 200 lb.
Ho: mu >= 200
Ha: mu < 200
------
n= 54; s = 121.2, x-bar = 183.9, alpha = 0.10
------
If you use a z-test you get:
test statistic = -0.97516.. and p-value=0.164493...
Conclusion: Since p>10%, Fail to reject Ho.
-----
If you use a t-test you get:
test statistic = -0.976158... and p-value = 0.1667104
so you would still "Fail to Reject Ho".
================================================
Test the given claim using the traditional method of hypothesis testing. Assume that the sample has been randomly selected from a population with a normal distribution.
-----------------------------------
7) A large software company gives job applicants a test of programming ability and the mean for that test has been 160 in the past. Twenty-five job applicants are randomly selected from one large university and they produce a mean score and standard deviation of 183 and 12, respectively. Use a 0.05 level of significance to test the claim that this sample comes from a population with a mean score greater than 160.
Ho: u = 160
Ha: u > 160
--------------
n=25; sample mean = 183, s=12, alpha = 5%
------
z-test results: test statistic = 9.583333... p-value = 1.0000
since p is greater than 5%, Fail to reject Ho.
------
t-test results: test stat= 9.58333; p-value = 0.9999999
Conclusion: same as z-test
------
Comment: I have a feeling that your posted data for the 2nd
question is not accurate. Is that standard deviation really 12?
==============================
Cheers,
Stan H.
|
|
|
