SOLUTION: solve for x 8^x+1= 19

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Question 171557: solve for x
8^x+1= 19
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Not sure whether you mean 8%5E%28x%2B1%29=19 or 8%5Ex%2B1=19

8%5E%28x%2B1%29=19

log%2810%2C%288%5E%28x%2B1%29%29%29=log%2810%2C%2819%29%29

%28x%2B1%29%28log%2810%2C%288%29%29%29=log%2810%2C%2819%29%29

x%2B1+=++log%2810%2C%2819%29%29%2F%28log%2810%2C%288%29%29+%29

x=++%28log%2810%2C%2819%29%29%2F%28log%2810%2C%288%29%29+%29%29%2B1

Or:

8%5Ex%2B1=19

8%5Ex=18

log%2810%2C%288%5Ex%29%29=log%2810%2C%2818%29%29

x%28log%2810%2C%288%29%29%29=log%2810%2C%2818%29%29

x=++log%2810%2C%2818%29%29%2F%28log%2810%2C%288%29%29+%29

Either way, leave the answer as it is, or you can do your own calculator work if you need a numerical approximation.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve for x
8^(x+1) = 19
Take the log of both sides to get:
(x+1)log8 = log19
x+1 = [log19]/[log8]
x+1= 1.4159756
x = 0.4159756
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Cheers,
Stan H.