SOLUTION: Complete the square. 1. x2 + 60x + 2. x2 – 7x + Solve each equation by completing the square. 3. x2 – 6x – 16 = 4. x2 – 14x + 74 = 0 5.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Complete the square. 1. x2 + 60x + 2. x2 – 7x + Solve each equation by completing the square. 3. x2 – 6x – 16 = 4. x2 – 14x + 74 = 0 5.      Log On


   

Question 171525:
Complete the square.
1. x2 + 60x +
2. x2 – 7x +

Solve each equation by completing the square.
3. x2 – 6x – 16 =

4. x2 – 14x + 74 = 0

5. 3x2 + 5x – 28 = 0

6. 4x2 – 6x + 3 = 0


Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Solve by completing the square

Step 1: Add the additive inverse of the constant term to both sides, leaving the constant term on the right.

ax%5E2%2Bbx%2Bc=0

ax%5E2%2B+bx=-c

Step 2: If the coefficient on the x%5E2 term is other than 1, divide all terms by this coefficient.

x%5E2%2B+%28b%2Fa%29x=-c%2Fa

Step 3: Divide the coefficient on the x term by 2 and square the result.

%28b%2F2a%29%5E2=%28b%5E2%29%2F%284a%5E2%29



Step 4: Add the result of Step 3 to both sides of your equation.



Step 5: You now have a perfect square polynomial on the left, so factor it.

%28x%2B%28b%2F2a%29%29+=%28-c%2Fa%29%2B%28b%5E2%29%2F%284a%5E2%29

Step 6: Simplify the right side as much as possible, then take the square root of both sides of the equation, remembering to include both the positive and negative root.

%28x%2B%28b%2F2a%29%29+=++sqrt%28%28%28b%5E2%29-%284ac%29%29%2F%284a%5E2%29%29 or %28x%2B%28b%2F2a%29%29+=++-sqrt%28%28%28b%5E2%29-%284ac%29%29%2F%284a%5E2%29%29

Step 7: Simplify and solve for x

x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29+

For your first two problems, just do steps 3 and 4. For the rest, follow the entire process. Hope that helps.