SOLUTION: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes are doubled and the number of nickels were increased by 8, the value of the coins would be $1
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Question 171421: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes are doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes are doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have?
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Value equation: 5n + 10d = 565 cents
value equation:5(n+8)+10(2d)=1045 cents
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Rearrange:
5n + 10d = 565
5n + 20d = 1005
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10d = 440
d = 44 (# of dimes)
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Substitute to solve for "n":
5n + 440 = 565
5n = 125
n =25 (# of nickels)
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Cheers,
Stan H.
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