SOLUTION: consider the function f(x)=x^2-6x+2 find h the x-coordinate of the vertex of this parabola.

Algebra ->  Coordinate-system -> SOLUTION: consider the function f(x)=x^2-6x+2 find h the x-coordinate of the vertex of this parabola.      Log On


   

Question 171395This question is from textbook pearson prentice hall
: consider the function f(x)=x^2-6x+2 find h the x-coordinate of the vertex of this parabola. This question is from textbook pearson prentice hall

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

In order to find the vertex, we first need to find the x-coordinate of the vertex.


To find the x-coordinate of the vertex, use this formula: x=%28-b%29%2F%282a%29.


x=%28-b%29%2F%282a%29 Start with the given formula.


From y=x%5E2-6x%2B2, we can see that a=1, b=-6, and c=2.


x=%28-%28-6%29%29%2F%282%281%29%29 Plug in a=1 and b=-6.


x=%286%29%2F%282%281%29%29 Negate -6 to get 6.


x=%286%29%2F%282%29 Multiply 2 and 1 to get 2.


x=3 Divide.


So the x-coordinate of the vertex is x=3. Note: this means that the axis of symmetry is also x=3.



Since the x-coordinate of the vertex is x=3, this means that h=3