SOLUTION: I apologize if this is in the wrong heading. My problem is systems of linear equation by substitution. { y=4x { y=2x+6
I am not sure how to do this problem. I tried getting the
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Coordinate Systems and Linear Equations
-> SOLUTION: I apologize if this is in the wrong heading. My problem is systems of linear equation by substitution. { y=4x { y=2x+6
I am not sure how to do this problem. I tried getting the
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Question 171363: I apologize if this is in the wrong heading. My problem is systems of linear equation by substitution. { y=4x { y=2x+6
I am not sure how to do this problem. I tried getting the numbers to match up so i could figure it out, but i cant seem to grasp it. Sorry if you cannot solve this problem and i'm sorry for wasting your time, but i am about ready to give up. This is a worksheet, and not from a book, by the way.
You can put this solution on YOUR website! My problem is systems of linear equation by substitution. { y=4x { y=2x+6
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y=4x
y=2x+6
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Then 4x = 2x+6 (they both = y)
2x = 6
x = 3
y = 12
You can put this solution on YOUR website! your 2 equations are:
y = 4x
y = 2x+6
since both equations equal to y, then they both must be equal to each other.
so.......
4x = 2x + 6
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this is the same as saying substitute 4x for y in the second equation because y = 4x from the first equation.
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4x = 2x + 6
simplify:
2x = 6
x = 3
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now you have x, you can solve for y.
in the first equation.
y = 4x
y = 4*3)
y = 12
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in the second equation.
y = 2x + 6
y = 2*3 + 6
y = 6 + 6
y = 12
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you get the same value of y and x in both equation so you have solved them simultaneously.
x = 3
y = 12
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