SOLUTION: A wall of a tent is shaped like a triangle and has an area of 48 square feet. The base of the wall is 2 feet shorter than 3 times the height. Find the length of the base and the h
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Question 171333: A wall of a tent is shaped like a triangle and has an area of 48 square feet. The base of the wall is 2 feet shorter than 3 times the height. Find the length of the base and the height of the wall.
My Work:
A= 1/2bh ------ b=3x-2 --------- h=x
A= 1/2 bh --------- 48= 1/2(3x-2)(x)------- 48=1/2(3x^2-2x)---------- 96=3x^2-2x---- 0= 3x^2-2x-96--------- 0=(3x-?)(x+?)
*** the carrot 2 means "three x squared" Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! 48=bh/2
48=(3h-2)h/2
48=(3h^2-2h)/2
3h^2-2h=48*2
3h^2-2h=96
3h^2-2h-96=0
(3h+16)(h-6)=0
h-6=0
h=6 ans.
b=3*6-2
b=18-2
b16 ans.
Proof:
48=6*16/2
48=96/2
48=48
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