Question 171204: given that loga2= 0.693, and loga11= 2.398, find loga 1/22
given that log x = 3 and log y = 6, find log xy2
Answer by oscargut(2103)   (Show Source):
You can put this solution on YOUR website! given that loga2= 0.693, and loga11= 2.398, find loga 1/22
loga(1/22)=loga(1)-loga(22)=0-loga(2*11)=-(loga(2)+loga(11))=-(0.693+2.398)=-3.091
given that log x = 3 and log y = 6, find log xy2
log(xy^2)=log(x)+log(y^2)=log(x)+2log(y)=3+2(6)=15
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