SOLUTION: find three consecutive odd integers such that three times the second minus the third is 11 more than the first

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Question 171121: find three consecutive odd integers such that three times the second minus the third is 11 more than the first
Answer by oscargut(2103) About Me  (Show Source):
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let n,n+2 and n+4 the numbers
three times the second minus the third is 11 more than the first
then
3(n+2)-(n+4)=n+11
2n+2=n+11
n=9
then
numbers are
9,11,13