SOLUTION: how do i write y-13=4(x-2)in standard form? It's On page 290.

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Question 171091This question is from textbook Algebra 1
: how do i write y-13=4(x-2)in standard form? It's On page 290. This question is from textbook Algebra 1

Found 2 solutions by jim_thompson5910, Mathtut:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
y-13=4%28x-2%29 Start with the given equation.


y-13=4x-8 Distribute.



y=4x-8%2B13 Add 13 to both sides.


y-4x=-8%2B13 Subtract 4x from both sides.


-4x%2By=5 Rearrange the terms.


So now the equation is in standard form Ax%2BBy=C where A=-4, B=1, and C=5

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
y-13=4(x-2)...given
:
y-13=4x-8.....distribute
:
4x-y-8=-13....subtract y from each side
:
highlight%284x-y=-5%29.......add 8 to each side