SOLUTION: Two planes left at the same time from two airports which are 4,500 miles apart and flew toward each other. In 5 hours, they passed each other. The rate of the fast plane was twic
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Question 171054: Two planes left at the same time from two airports which are 4,500 miles apart and flew toward each other. In 5 hours, they passed each other. The rate of the fast plane was twice the rate of the slow plane. Find the rate of each plane. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Two planes left at the same time from two airports which are 4,500 miles apart and flew toward each other. In 5 hours, they passed each other. The rate of the fast plane was twice the rate of the slow plane. Find the rate of each plane.
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Their combined rates = 4500 miles/5 hrs = 900 mph
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EQUATION:
Their rates are 2x and x
2x+x = 900
3x = 900
x = 300 mph (rate of slow plane)
2x = 600 mph (rate of fast plane)
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Cheers,
Stan H.
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